We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
<h3>
Answer: 9</h3>
========================================================
Work Shown:
Apply the pythagorean theorem
a^2 + b^2 = c^2
12^2 + b^2 = 15^2
144 + b^2 = 225
b^2 = 225-144
b^2 = 81
b = sqrt(81)
b = 9
Step-by-step explanation:
1) the domain is from -3 to 5 D [-3,5]
the range is from -5 to -2. R [-5,-2]
2)the domain is from -3 to 6 but not including 6 D [-3,6)
the range is from -5 but not including -5 to 2. R (-5,2]
