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lord [1]
3 years ago
14

Geometry question..can anyone help?

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

For the trapezoid it is the y axis.....

For the triangles it is the x axis

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It is your birthday and you are going to get a new cell phone. The day you buy the phone, you will have to pay the $49 interest
Juli2301 [7.4K]

Answer:

30.46

Step-by-step explanation:

4 0
3 years ago
Let f(x) =(x-3) find the domain of x
m_a_m_a [10]

Answer:

all real numbers

Step-by-step explanation:

The domain of a function is the set of values you can set as x to output an answer. Since you can subtract 3 from any real number, the domain of x-3 is all real numbers.

5 0
3 years ago
The inside ring of packing tape has a diameter of 80 mm. The tape surrounding the ring is 8 mm beyond the ring. What is the dist
Nutka1998 [239]

Answer:

301.44 mm

Step-by-step explanation:

Diameter of the inside ring of a packing tape = 80 mm

The tape surrounding the ring is 8 mm beyond the ring which means the diameter of the ring including the surrounding will be:

80 + 8 + 8 = 96 mm

and its radius will be = 96/2 = 48.

To find the distance around the outer edge of the tape, we need to calculate the circumference for the ring with the tape on it.

<em>Circumference = 2\pi r </em>

Circumference = 2 x 3.14 x 48 = 301.44 mm

Therefore,  the distance around the outer edge of the tape is 301.44 mm.

6 0
3 years ago
A group consists of 6 men and 5 women. Five people are selected to attend a conference. In how many ways can 5 people be selecte
cluponka [151]

Answer:

462

6

1.2%

Step-by-step explanation:

Since the questions are combinations, we must apply the combination formula, which is as follows:

n C r = (n!) / (r! (n-r)!)

Because there are 6 men and 5 women, there are a total of 11 people.

Thus:

n = 11

In the first question in how many ways can 5 people be selected from this group of 11, r = 5.

Replacing in the formula:

11 C 5 = (11!) / (5! * (11-5)!)

11 C 5 = (11!) / (5! * 6!)

11 C 5 = 462

In the second question, in how many ways can 5 men be selected from the 6 men, here n = 6 and r = 5, replacing we are left with:

6 C 5 = (6!) / (5! * (6-5)!)

6 C 5 = (6!) / (5! * 1!)

6 C 5 = 6

In the last question of what is the probability that the selected group is all men, we have that it is the combination of the two previous questions. Since the total would be part A it would be the total of the combinations of choosing 5 of 11 people and part B of the 6 men that there are the combinations of choosing 5.

Divide the two values ​​from parts A and B to get ...

(result from part B) / (result from part A) = (# of ways to pick 5 men) / (# of ways to pick 5 people)

(result from part B) / (result from part A) = 6/462

(result from part B) / (result from part A) = 0.012

In other words, the probability is 1.2%

7 0
3 years ago
Factor 81 – 27p..........................................................
Dafna1 [17]
<span>In order to factor the equation we must first find the highest number divisible by both 81 and 27p. In this case both 81 and 27 are divisible by 27. Once you take 27 from both 81 and 27p you are left with (27)(3-p)...................</span>
7 0
3 years ago
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