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Llana [10]
2 years ago
9

Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the

Mathematics
1 answer:
MAVERICK [17]2 years ago
5 0

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

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So I guess we are solving for x here :)
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a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

It's  x=a/2(1+3z)
5 0
3 years ago
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-2 &lt; n s6<br><br> n is an integer.<br><br> What are the possible values of n?
alex41 [277]
This is what I found

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2 years ago
Segment CB is a____
Dahasolnce [82]

Answer:

Radius

Step-by-step explanation:

CB = AB/2

Since AB is the diameter, CB is a radius

5 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
HELP!! I only need the answer. Thank you!
zvonat [6]
The answer would be 6 3/8

Hope this helps c:
5 0
2 years ago
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