Answer: 
or 
.
Step-by-step explanation:
Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.
The total number of cards in a deck 52
Number of faces cards in a deck = 12
Number of cards not face cards = 40
The total number of combinations of drawing 9 cards out of 52 cards = 
Now , the combination of 9 cards such that exactly 6 of them are face cards = 
Now , the probability that the hand contains exactly 6 face cards will be :-
![=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Cdfrac%7B12%21%7D%7B6%216%21%7D%5Ctimes%5Cdfrac%7B40%21%7D%7B3%2137%21%7D%7D%7B%5Cdfrac%7B52%21%7D%7B9%21%5Ctimes43%21%7D%7D%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B228%7D%7B91885%7D)
Hence, the probability that the hand contains exactly 6 face cards. is .
Answer:
Number of student tickets were sold = 409
Step-by-step explanation:
Total number of tickets sold = 771
I.e Students ticket (S) + Non students ticket(N S) = 771
Total amount to be paid for tickets = $ 3037
Amount paid by students per tickets = $3
Amount paid by non-students per tickets = $5
So, according to question
S + NS = 771
3 S + 5 NS = 3037
Solve both equations
5 S + 5 NS = 771 × 5
3 S + 5 NS = 3037
so ,
(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037
Or, 2 S = 818
I.e S = 
= 409
Hence, The number of student tickets were sold = 409 Answer
Answer:
-9/5 , -8/5 , -7/5, -6/5 , -5/5.
Step-by-step explanation:
brainliest plsssss
Answer:
Algebracicaly speaking the answer would be either -13.3876 or - 158.612 through the quadratic equation, but these answers don’t make sense in this real world scenario.
Step-by-step explanation:
Answer:
100 degrees
Step-by-step explanation:
measure of FHD = 65 + 35
measure of FHD = 100
