I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music I'm living' in that 21st century
Doing something mean to it
Do it better than anybody you ever seen do it
Screams from the haters, got a nice ring to it
I guess every superhero need his theme music
16x + 9 = 9y-2x Add 2x to both sides
18x + 9 = 9y Divide both sides by 9
2x + 1 = y Switch the sides to make it easier to read
y = 2x + 1
Answer:
Step-by-step explanation:
This is an exponential equation that is solved by taking the natural log of both sides. The equation is
![f(x)=2^x](https://tex.z-dn.net/?f=f%28x%29%3D2%5Ex)
If we are looking for x when f(x) = 64, then
![64=2^x](https://tex.z-dn.net/?f=64%3D2%5Ex)
Take the natural log of both sides:
![ln(64)=ln(2^x)](https://tex.z-dn.net/?f=ln%2864%29%3Dln%282%5Ex%29)
The rules of logs allows us to bring the x down in front:
![ln(64)=xln(2)](https://tex.z-dn.net/?f=ln%2864%29%3Dxln%282%29)
Divide both sides by ln(2) to get:
![\frac{ln(64)}{ln(2)}=x](https://tex.z-dn.net/?f=%5Cfrac%7Bln%2864%29%7D%7Bln%282%29%7D%3Dx)
Do this on your calculator to get that x = 6.
You could also have just gone right to your calculator and started raising 2 to consecutive powers starting at like 3 or 4 to eventually get that 2 to the 6th power is equal to 64, but for the basics of solving log equations, you need to know how to do this.
Answer:
x=15is your answer
Step-by-step explanation:
8x=120 vertically opposite angle
x=120/8=15