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andrey2020 [161]
3 years ago
9

The focus of a parabola is (−5,−1) and the directrix is y=−3.

Mathematics
1 answer:
Bingel [31]3 years ago
8 0
(x+5)^2=4(y+2)

the equation for a parabola with focus (h, k+p) and directrix y=k-p is 
(x-h)^2=4p(y-k)

so using your directrix y=-3, and knowing directrix is y=k-p, you have 
-3=k-p.
similarly, knowing the focus is defined by (h,k+p) and your focus is (-5,-1)
you have the equation -1=k+p.

you now have a system of equations
-3=k-p \\ -1=k+p
which you can solve using any method, I will use elimination.
adding down
-4=2k \\ -2=k
you now have k and can find p using either equation. 
-3=k-p \\ -3=-2-p \\ -1=-p \\ 1=p.

now you plug those in, getting the answer
(x+5)^2=4(y+2)
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Lines AC←→ and DB←→ intersect at point W. Also, m∠DWC=138° .
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Solution:

Line \overrightarrow{A C} \text { and } \overrightarrow{B D} intersect at a point W.

Given m \angle D W C=138^{\circ}.

<em>Vertical angle theorem:</em>

<em>If two lines intersect at a point then vertically opposite angles are congruent.</em>

<u>To find the measure of all the angles:</u>

∠AWB and ∠DWC are vertically opposite angles.

Therefore, ∠AWB = ∠DWC

⇒ ∠AWB = 138°

Sum of all the angles in a straight line = 180°

⇒ ∠AWD + ∠DWC = 180°

⇒ ∠AWD + 138° = 180°

⇒ ∠AWD = 180° – 138°

⇒ ∠AWD = 42°

Since ∠AWD and ∠BWC are vertically opposite angles.

Therefore, ∠AWD = ∠BWC

⇒ ∠BWC = 42°

Hence the measure of the angles are

m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°.

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