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il63 [147K]
2 years ago
10

Select all the correct answers.

Mathematics
1 answer:
alina1380 [7]2 years ago
3 0

sorry i just want some points :)

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SIMPLIFY THIS EXPRESSION:<br> 2(z + 3) + 3(5 - 3z)
quester [9]
2z+6+15-9z
-7z+21

Hope this helps
6 0
3 years ago
(-x + 3) + (x + 5) = i need a step by step explanation plz
ddd [48]

Answer:

(-x+3)+(x+5)= -x+3+x+5. =now add the numbers -x+8+x = now combined like terms = 8 now 8 is the answer

5 0
3 years ago
Help me<br> Verified and certified by me<br> -ayyyyyyy
spayn [35]

Answer:

c. 412.5 cm^2

Step-by-step explanation:

first triangle: 5 x 15 = 75

75/2 = 37.5

rectangle:  15 x 19 = 285

triangle 2: 15 x 12 = 180

180/2 = 90

37.5 + 285 + 90 = 412.5

3 0
2 years ago
Find the missing side length leave your answers as radicals in the simplest form.
ira [324]

Answer:

Part 1) x=\frac{10\sqrt{3}}{3}\ units

Part 2) y=5\ units

Step-by-step explanation:

step 1

Find the value of x

In the right triangle of the figure

sin(30^o)=\frac{(5\sqrt{3}/3)}{x} ---> opposite side angle of 30 degrees divided by the hypotenuse

Remember that

sin(30^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{(5\sqrt{3}/3)}{x}

solve for x

x=\frac{5\sqrt{3}}{3}(2)

x=\frac{10\sqrt{3}}{3}\ units

step 2

Find the value of y

In the right triangle of the figure

cos(30^o)=\frac{y}{x} ---> adjacent side angle of 30 degrees divided by the hypotenuse

we have

x=\frac{10\sqrt{3}}{3}\ units

cos(30^o)=\frac{\sqrt{3}}{2}

substitute

\frac{\sqrt{3}}{2}=\frac{y}{\frac{10\sqrt{3}}{3}}    

y=(\frac{\sqrt{3}}{2})(\frac{10\sqrt{3}}{3})

y=5\ units

4 0
3 years ago
The world's heaviest man is reported to have had a mass of 635 kg what was his weight
nataly862011 [7]

Answer:

about 6230 N

Step-by-step explanation:

The mass is given to 3 significant figures, so we need a value for the acceleration due to gravity that is at least 3 significant figures. The standard value is 9.80665 m/s². Using that, the force is ...

... F = ma = (635 kg)(9.80665 m/s²) = 6227.22275 N

Since the mass is only good to 3 significant figures, the force must be rounded to that precision: 6230 N.

3 0
3 years ago
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