M + e + f = 11
e = 1/5m
f = 3m
m + 1/5m + 3m = 11 <== ur equation
5/5m + 1/5m + 15/5m = 11
21/5m = 11
m = 11 / (21/5)
m = 11 * 5/21
m = 55/21
m = 2.619 rounds to 2.62...milk
e = 1/5m
e = 1/5(2.62)
e = 0.53 .....eggs
f = 3m
f = 3(2.62)
f = 7.86...fabric softener
36 cupcakes if one cup of flour is 6 cupcakes you multiply the amount of flour by 6
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
The solution to the problem is as follows:
<span>
cot θ = cos θ / sin θ </span>
<span>So sinθ * cot θ = cos θ after cancelling sin θ </span>
<span>Now cosθ + sin θ cot θ = cos θ + cos θ = 2 cos θ
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
Step-by-step explanation:
no
