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3 years ago

Please help with this problem?

Mathematics

1 answer:

TiliK225 [7]3 years ago

4 0

I believe its b .... i had just done something like that on my compass learning and it is somehow like the same so i worked it out and i think its b

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Daniels print shop purchased a new printer for $35,000. Each year it depreciates at rate of 5%. How much will the printer be wor

Savatey [412]

Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:
About $23219.72

Let me know if you have any questions :)

7 0

3 years ago

A "centroid" is defined as the center of mass of an object, or shape. How might the midpoint formula be used to find the midpoin

lesantik [10]

Answer:

we can use centeroid formula of a triangle

that is (x1+x2+x3)/3

hope that helps : )

6 0

3 years ago

Which polygon appears to be regular?

ivolga24 [154]

Answer:

Figure A

Step-by-step explanation:

A regular polygon has all sides the same length and all angles the same measure. Only Figure A matches that description.

5 0

3 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

Three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the r

julia-pushkina [17]

Answer:

Step-by-step explanation:

Given that three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the remaining 21%.

Their on-time rates are 83%, 66%, and 36%, respectively.

Airlines A B C

Flights 52% 27% 21% 100%

On time rates 83% 66% 36%

Flight*online rates 43.1600% 17.8200% 7.5600% 68.5400%

Thus the above table shows the product of no of flights and on time rates.

Prob it was airline A given it left on time

= $\frac{43.16}{68.54} \\=0.6297$

4 0

3 years ago