Pizzas cost $8 and sandwiches cost $2.50
So first you distribute the 5 to the x and the +2 and get
5x+10=3(x+8)
then you distribute the 3 to the other x and the +8 and get
5x+10=3x+24
subtract 3x from both sides
2x+10=24
subtract 10 from both sides and get
2x=14
divide both sides by 2 and get
x=7
<h3>
Answer: 5 < x < 29</h3>
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Explanation:
Since AB is smaller than AD, this must mean the angle ACB is smaller than angle ACD. Note how these angles are opposite the sides mentioned.
So 2x-10 < 48
At the same time, 2x-10 is also larger than 0.
Overall, we can say 0 < 2x-10 < 48
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Let's solve for x
0 < 2x-10 < 48
0+10 < 2x < 48+10 ...... add 10 to all sides
10 < 2x < 58
10/2 < x < 58/2 ..... divide all sides by 2
5 < x < 29
Answer:
(IQR) interquartile range = 5
Step-by-step explanation:
Lower quartile: 48
Upper quartile: 53
Median: 52
Lowest value: 46
Highest value: 55
(IQR) interquartile range: Upper quartile - Lower quartile = final answer
(IQR) interquartile range: 53 - 48 = 5