In the balanced reaction
2 Fe + O₂ → 2 FeO
2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.
Look up the molar mass of Fe and O:
• Fe = 55.845 g/mol
• O = 15.999 g/mol
Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is
(42.4 mol) × (71.835 g/mol) ≈ 3050 g
Answer:
A = 307.9 sq/cm
Step-by-step explanation:
Find the radius of the semi-circle
diameter + half the circumference = 72 cm
2r + pi*r = 72
r(2+pi) = 72
r = 72%2F%28%282%2Bpi%29%29
r = 14
:
what will be the area of that semicircle?
A =1%2F2*pi%2A14%5E2
A = 307.9 sq/cm
Answer:
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Step-by-step explanation:
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know is this is 64?creó piensas jdnd
Answer:
C
Step-by-step explanation:
