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2 years ago

2x10^-5 i need help please

Mathematics

1 answer:

densk [106]2 years ago

3 0

Answer:

1/50000

Step-by-step explanation:

Sorry if this wasn't helpful! this was the only logical answer i had!

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What would be the concentration if we were to mix 200g of 10% sugar solution and 300g of 20% sugar solution?

Firdavs [7]

+ 200g of 10% sugar solution: there is 200*10%= 20 g
+ 300g of 20% sugar solution: 300*20%= 60 g
The total of sugar: 20+60= 80g
And The concentration is 80:(200+300)= 80:500= 16%
Have fun

6 0

3 years ago

How many litres of milk can be put in six hemispherical bowl each of diameter 35cm

Lesechka [4]

Answer:

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

Step-by-step explanation:

The volume of a hemisphere ( $V$ ), measured in cubic centimetres, is obtained from this formula:

$V = \frac{2\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the hemisphere, measured in centimetres.

We know that radius is the half of the diameter ( $D$ ), measured in centimetres, then:

$R = 0.5\cdot D$

( $D = 35\,cm$ )

$R = 0.5\cdot (35\,cm)$

$R = 17.5\,cm$

Now, we get the volume of each hemispherical bowl:

$V = \frac{2\pi}{3} \cdot (17.5\,cm)^{3}$

$V \approx 11224.649\,cm^{3}$

The total volume of six hemispherical bowl is:

$V_{T} = 6\cdot V$

$V_{T}= 6\cdot (11224.649\,cm^{3})$

$V_{T} = 67347.894\,cm^{3}$

From Physics we know that 1 litre equals 1000 cubic centimetres. Then:

$V_{T} = 67.348\,L$

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

3 0

3 years ago

If the zeros of a parabola are at x = 4 and x = -2 what could be the equation of the parabola?

AURORKA [14]

Answer:

the equation would be: y=(x-4)(x+2)

8 0

2 years ago

My teacher likes to give me stuff I haven’t learned

TEA [102]

Answer:

42 I think

Step-by-step explanation:

4 0

2 years ago

A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus

xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± $z\frac{\sigma}{\sqrt n}$

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 27.4 - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 21.79

Upper limit of Confidence interval = μ + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 27.4 + $2.58\times\frac{5.75}{\sqrt{7}}$

Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

5 0

3 years ago