Answer:
the answer is 1.2370 .. give me brainliest
Answer:
8a+5b-9
Step-by-step explanation:
(8a+2b-4)+(3b-5)
8a+2b+3b-4-5
8a+5b-9
10 plays
Divide 2/5 and 4 by 2 to get 1/5 and 2
For every 1/5 of practice he teaches the ten 2 plays
5/5 = 1
So 5*2 = 10 plays
There are eight cities on the list.
The number of groups of 2 is (8·7)/2 = 28
The number of groups of 3 is (8·7·6)/(3!) = 56
The number of groups of 4 is (8·7·6·5)/(4!) = 70
The number of groups of 5 is (8·7·6·5·4)/(5!) = 56
The number of groups of 6 is (8·7·6·5·4·3)/(6!) = 28
The number of groups of 7 is (8·7·6·5·4·3·2)/(7!) = 8
So there are (28+56+70+56+28+8) = 246 ways to visit "some" of them.
There's only one way to visit "all" of them, and
there's only one way to visit "none" of them.
So, all together, Louise has 248 travel options.
If she decides to visit Chicago, I will show her a good time.
Hi!
Let's first expand the cotangent of theta.
You'll probably know that tangent will be "y/x", or 
, and cotangent is the reciprocal of this, meaning that it is "x/y" or 
.
That means that we are now given this equation.
That'll multiply to:
We'll want a common denominator to add by multiplying 
to both top and bottom of the second term:
Pythagorean Identity states that 
, so substitute that in:
Which simplifies to:
Hope this helps!
