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SVEN [57.7K]
3 years ago
10

Cheryl has twice as many nickels as quarters and five more dimes than nickels.

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

2 quarters

4 nickels

9 dimes

Step-by-step explanation:

quarters = x

nickels = 2x

dimes = 2x+5

25x+5(2x)+10(2x+5)=160

25x+10x+20x+50=160

55x=160-50

55x=110

x=2

SO:

(x) = 2 quarters

(2x) = 4 nickels

(2x+5) = 9 dimes

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So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
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1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
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First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
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7 0
3 years ago
PLEASE HELP!
Orlov [11]
We have that
<span>If (5x-4+13x=5) -------------->  then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then 
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>


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