Answer:
Step-by-step explanation:
The diagram shows lines passing through the points of two equations.
We will determine the points through which the lines pass through on the graphs.
Looking at the line on the right hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 4
x2 = 3, x1=0
Slope, m = (0-4)/3-0
Slope = -4/3
Recall the equation of a straight line is y = mx + c
Where c is the intercept.
So the equation is y
y = -4x/3 + 4
Looking at the line on the left hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 2
x2 = -1, x1 =0
Slope, m = (0-2)/-1-0
Slope = -2/-1 = 2
Applying equation of a straight line is y = mx + c
The equation
y = 2x + 2
So the equations are
-4x/3 + 4. If x lesser than or equal 0
2x + 2. If x greater than 0
C) 1 b =-2. D) 7 f(-2) = 3(-8) - 2. -5 x=6
y. 4(y + 1) = x. If (x, y) is the solution to
the system of equations.
The answer to this one is<em> xy + 4</em>
