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cestrela7 [59]
3 years ago
6

The derivative of y=x^(1+√2)

Mathematics
1 answer:
elixir [45]3 years ago
3 0

The power rule tells you

(d/dx)(x^n) = n·x^(n-1)

You have n=1+√2, so your derivative is

... dy/dx = (1+√2)·x^(√2)

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[tex]\sqrt{x} 196<br> can someone help me
Maslowich

Answer:

14

Step-by-step explanation:

√196

Calculate the square root of 196 and get 14.

14

8 0
3 years ago
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What is the value of m in the equation 4m + 2(m + 1) = 9m + 5
ratelena [41]
M=-1 

4m+2(m+1)=9m +5
4m+2m+2=9m+5
6m+2=9m+5
6m+2-6m= 9m+5-6m
2-5=3m+5-5
-3/3=3m/3
m=-1
3 0
3 years ago
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Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
4 years ago
I want to just get in with life.
Ahat [919]

Answer:

The equation would be y = -2x + 1

Step-by-step explanation:

All you have to do is put it in the form y = mx + b where m is the slope and b is the y-intercept (for example, the equation y= 2x + 1 has a slope of 2 and a y-intercept of 1.)

Since you have slope, or m, = -2 and the y-intercept, or b, = 1, the equation would be y = -2x + 1

4 0
3 years ago
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5 1/4 of what number is 42
amid [387]

Answer:

8

Step-by-step explanation:

5 1/4 =5.25

42/5.25 = 8

8×5.25 = 42

4 0
3 years ago
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