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3 years ago

Which polynomial is twice the sum of 4x^2-x+1 and -6x^2+x-4

Mathematics

1 answer:

Ilya [14]3 years ago

4 0

-4x^2 - 6

When you add them together it gives a sum of -2x^2 - 6. Multiplying that by 2 gives you the above answer.

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Look at the right triangle ABC:

prisoha [69]

Answer:

The first incorrect justification is in step 2.

Step-by-step explanation:

<u>Step 2</u>. BC2 = AC • DC

2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC

It's supposed to be AC ÷ BC not BC ÷ AC.

8 0

3 years ago

#10 AH IM STUCK ON THIS ITS HARD HELP

Dafna11 [192]

Answer:

4.8 in

Step-by-step explanation:

feet to inch conversion is *12

2 * 12 = 24

then divide the scale (for every 1 in on the model there is 5 in on the actual, so divide the actual value by 5)

24/5 = 4.8

your answer is 4.8 in

hope this helps:)

6 0

2 years ago

HELP me plzzzz i need to finish this

trapecia [35]

Answer:

725.95

Step-by-step explanation:

If you multiply 129.95*5. You get 649.75, but you have to add 76.20 from the delivery and you get 725.95

Hope this helps =)

4 0

2 years ago

Expression using the numbers 7,5,6,3 to equal 75

Inga [223]

(7 + 5) x 6 + 3. (7 + 5 = 12, 12 x 6 = 72, 72 + 3 = 75.)

5 0

3 years ago

What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?

kvasek [131]

Answer:

The center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

here,

r = raduis

center = (a, b)

Given the equation

$\left(x-14\right)^2+\left(y+21\right)^2=64$

$\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2$

comparing with the circle equation

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

Therefore, the center of the circle is:

$\left(a,\:b\right)=\left(14,\:-21\right)$

Thus, option (2) is true.

7 0

2 years ago