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marin [14]
3 years ago
12

The ratio of collectible cards Kyle owns to cards that Zeona owns is 3:2. Zeona has 36 cards. How will the ratio of Kyle’s cards

to Zeona’s cards change if they both sell half of their cards? Explain.
Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

It wouldn't.

Step-by-step explanation:

With the ratio, since Zeona has 36 cards, Kyle must have 54. If they each sold half, Kyle would have 27 and Zeona would have 18. So, the ratio would still be 3:2.

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Each gallon of gasoline costs $2.35. The equation y=2.35x can be used to represent this situation.
Gnom [1K]

Answer:

Yes

Step-by-step explanation:

If y is the total cost, then this would be correct.

7 0
3 years ago
Find the volumes of the solids whose bases are bounded by the circle x^2 + y^2 = 9, with the indicated cross sections taken perp
labwork [276]

<em>x</em> ^2 + <em>y</em> ^2 = 9   =>   <em>y</em> = <em>y(x)</em> = ± √(9 - <em>x</em> ^2)

Each cross section would be a square with side length equal to the vertical distance between the upper and lower semicircles defined by <em>y(x)</em>, which is

√(9 - <em>x</em> ^2) - (- √(9 - <em>x</em> ^2)) = 2 √(9 - <em>x</em> ^2)

The area of each square section is the square of this length,

(2 √(9 - <em>x</em> ^2)) = 4 (9 - <em>x</em> ^2) = 36 - 4<em>x</em> ^2

We get the whole solid for -3 ≤ <em>x</em> ≤ 3, so integrating gives a volume of

\displaystyle\int_{-3}^3(36-4x^2)\,\mathrm dx=\boxed{144}

3 0
3 years ago
100 points!!!! To whoever helps me with this!
netineya [11]

Answer:

#1: Josue's dogs

#2: see images

#3: Am group median: 25.5       Pm group median: 19

#4: Am group first Quartile = 16 Pm group first Quartile = 10

#5: Am group third Quartile = 30 Pm group third Quartile = 37

#6: see images

#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27

#8: Am group because its Interquartile gruop is smaller than the Pm group

Step-by-step explanation:

Mark as Brainliest

5 0
3 years ago
Read 2 more answers
How do I get the answer for 1 1/2 x 3 x 1 1/9
Mekhanik [1.2K]

\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}

<h2>Explanation:</h2>

in this problem we have the following expression:

1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}

So here:

1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions

Let's convert them as improper fractions:

1 \frac{1}{2}=1+\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2} \\ \\ 1 \frac{1}{9}=1+\frac{1}{9}=\frac{1\times9 +1}{9}=\frac{10}{9}

Rewriting our expression:

\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

#LearnWithBrainly

3 0
3 years ago
The difference between five times a number and twice that number
lara31 [8.8K]
<span>The difference between five times a number and twice that number = 15</span>
7 0
3 years ago
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