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3 years ago

I need help with answering this answer ASAP. Please help me

Mathematics

1 answer:

taurus [48]3 years ago

7 0

Factors are (y - 7)(5y - 43)

Step-by-step explanation:

Step 1: Given, 5x² + 12x + 4 = (x + 2)(5x + 2)

Now, to factor 5(y - 9)² + 12(y - 9) + 4. Here, y - 9 can be equated to x if both equations are compared.

Step 2: To factorize, substitute y - 9 for x in the factors (x + 2)(5x + 2)

⇒ Factors = (y - 9 + 2)[5(y - 9) + 2]

= (y - 7)(5y - 45 + 2)

= (y - 7)(5y - 43)

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3 years ago

What is the solution of

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Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

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Simplifying on the left side, and applying on the right side the formula:

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Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

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Factoring: Common factor x:

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1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

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$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

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Answer:

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