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ikadub [295]
3 years ago
13

You decide to go to the candy store in the mall. You arrive at the store with $25 and then purchase 3 candy bars. You then buy a

giant candy snake for $12.50. When you leave, you have $8.75 left in your wallet. How much did each candy bar cost? Write the equation to represent the scenario. 8.75 - x - 12.50 = 25.00 25.00 - 3x - 12.50 = 8.75 25.00 - 3x - 8.75 = 12.50 25.00x - 12.50 = 8.75
Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

<h2> The cost of a candy is $1.25</h2>

Step-by-step explanation:

given the total amount at hand is $25

let the price of  candy be x

then the cost of 3 candy will  be 3x

the cost of a candy snake is $12.50.

balance at hand after the end of buying $8.75

the total expenses summed up must equal the initial amount at hand which is $25

the expression for the scenario is 3x+12.5+8.75=25

3x+21.25=25

3x=25-21.25

3x=3.75

x=3.75/3

x=$1.25

The cost of a candy is $1.25

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Answer:

10+8x=y

Step-by-step explanation:

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Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

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2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

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Darina [25.2K]

Answer:

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Step-by-step explanation:

We can write an algebraic equation to solve this situation: x + x + 1 = 65, where x = first integer (small number) and x + 1 = the following integer.

Step 1: Combine like terms.

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Step 2: Subtract 1 from both sides.

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Step 3: Divide both sides by 2.

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Therefore, the smaller number is 32 while the larger number is 33.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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