Answer:
2x(5x+1)(2x+3)=0
Step-by-step explanation:
x{20x^2+34x+6}=0
2x(10x^2+17+3)=0
2x(10x^2+15x+2x+3)=0
2x{5x(2x+3)+1(2x+3)}=0
2x(5x+1)(2x+3)=0
EXPLANATION:
-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.
data:
-6 that must be added to a number.
-four times a number that is equal to 4x
-a result that is equal to 50
Now with these data we formulate the equation:

if we solve the equation we have:
When rates are expressed as a quantity of 1, such as 2 feet per second<span> or </span>5 miles per hour<span>, they are called unit rates. If you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term.</span>
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