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NeX [460]
2 years ago
7

PLEASE HELP

Mathematics
2 answers:
Tems11 [23]2 years ago
5 0

Answer:

1.

5

x

−

2

y

=

4

; (−1, 1)

2.

3

x

−

4

y

=

10

; (2, −1)

3.

−

3

x

+

y

=

−

6

; (4, 6)

4.

−

8

x

−

y

=

24

; (−2, −3)

5.

−

x

+

y

=

−

7

; (5, −2)

6.

9

x

−

3

y

=

6

; (0, −2)

7.

1

2

x

+

1

3

y

=

−

1

6

; (1, −2)

8.

3

4

x

−

1

2

y

=

−

1

; (2, 1)

9.

4

x

−

3

y

=

1

;

(

1

2

,

1

3

)

10.

−

10

x

+

2

y

=

−

9

5

;

(

1

5

,

1

10

)

11.

y

=

1

3

x

+

3

; (6, 3)

12.

y

=

−

4

x

+

1

; (−2, 9)

13.

y

=

2

3

x

−

3

; (0, −3)

14.

y

=

−

5

8

x

+

1

; (8, −5)

15.

y

=

−

1

2

x

+

3

4

;

(

−

1

2

,

1

)

16.

y

=

−

1

3

x

−

1

2

;

(

1

2

,

−

2

3

)

17.

y

=

2

; (−3, 2)

18.

y

=

4

; (4, −4)

19.

x

=

3

; (3, −3)

20.

x

=

0

; (1, 0)

Find the ordered pair solutions given the set of x-values.

21.

y

=

−

2

x

+

4

; {−2, 0, 2}

22.

y

=

1

2

x

−

3

; {−4, 0, 4}

23.

y

=

−

3

4

x

+

1

2

; {−2, 0, 2}

24.

y

=

−

3

x

+

1

; {−1/2, 0, 1/2}

25.

y

=

−

4

; {−3, 0, 3}

26.

y

=

1

2

x

+

3

4

; {−1/4, 0, 1/4}

27.

2

x

−

3

y

=

1

; {0, 1, 2}

28.

3

x

−

5

y

=

−

15

; {−5, 0, 5}

29.

–

x

+

y

=

3

; {−5, −1, 0}

30.

1

2

x

−

1

3

y

=

−

4

; {−4, −2, 0}

31.

3

5

x

+

1

10

y

=

2

; {−15, −10, −5}

32.

x

−

y

=

0

; {10, 20, 30}

Find the ordered pair solutions, given the set of y-values.

33.

y

=

1

2

x

−

1

; {−5, 0, 5}

34.

y

=

−

3

4

x

+

2

; {0, 2, 4}

35.

3

x

−

2

y

=

6

; {−3, −1, 0}

36.

−

x

+

3

y

=

4

; {−4, −2, 0}

37.

1

3

x

−

1

2

y

=

−

4

; {−1, 0, 1}

38.

3

5

x

+

1

10

y

=

2

; {−20, −10, −5}

Part B: Graphing Lines

Given the set of x-values {−2, −1, 0, 1, 2}, find the corresponding y-values and graph them.

39.

y

=

x

+

1

40.

y

=

−

x

+

1

41.

y

=

2

x

−

1

42.

y

=

−

3

x

+

2

43.

y

=

5

x

−

10

44.

5

x

+

y

=

15

45.

3

x

−

y

=

9

46.

6

x

−

3

y

=

9

47.

y

=

−

5

48.

y

=

3

Find at least five ordered pair solutions and graph.

49.

y

=

2

x

−

1

50.

y

=

−

5

x

+

3

51.

y

=

−

4

x

+

2

52.

y

=

10

x

−

20

53.

y

=

−

1

2

x

+

2

54.

y

=

1

3

x

−

1

55.

y

=

2

3

x

−

6

56.

y

=

−

2

3

x

+

2

57.

y

=

x

58.

y

=

−

x

59.

−

2

x

+

5

y

=

−

15

60.

x

+

5

y

=

5

61.

6

x

−

y

=

2

62.

4

x

+

y

=

12

63.

−

x

+

5

y

=

0

64.

x

+

2

y

=

0

65.

1

10

x

−

y

=

3

66.

3

2

x

+

5

y

=

30

Part C: Horizontal and Vertical Lines

Find at least five ordered pair solutions and graph them.

67.

y

=

4

68.

y

=

−

10

69.

x

=

4

70.

x

=

−

1

71.

y

=

0

72.

x

=

0

73.

y

=

3

4

74.

x

=

−

5

4

75. Graph the lines

y

=

−

4

and

x

=

2

on the same set of axes. Where do they intersect?

76. Graph the lines

y

=

5

and

x

=

−

5

on the same set of axes. Where do they intersect?

77. What is the equation that describes the x-axis?

78. What is the equation that describes the y-axis?

Part D: Mixed Practice

Graph by plotting points.

79.

y

=

−

3

5

x

+

6

80.

y

=

3

5

x

−

3

81.

y

=

−

3

82.

x

=

−

5

83.

3

x

−

2

y

=

6

84.

−

2

x

+

3

y

=

−

12

Step-by-step explanation:

Anastasy [175]2 years ago
4 0

Answer:

<h3>Step-by-step explanation: you would use the slop formula! First graph the points and draw the line (demos is a great virtual graphing website). Then use the Slop formula which is:</h3><h3></h3><h3>       y2 - y1</h3><h3>m=  ———-                  (1, -5)     (-3,  2)</h3><h3>       x2 - x1                  x1  y1      x2  y2</h3>

   

After filling in the formula and solving you’ll get 1.75 which is the same as 7/4

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Masja [62]
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6 0
3 years ago
There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per hour. At
kumpel [21]

Answer:

The required piece-wise linear function is

\left\{\begin{matrix}1.5x & 0\leq x

Step-by-step explanation:

Consider the provided information.

Let x represents the number of hours and S(x) represents the depth of snow.

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per.

That means the depth of snow will be:

S(x)=1.5x\ \ \ 0\leq x< 4

At  4:00 a.m., it starting falling at a constant rate of 3 inches per hour,

From mid night to 4:00 a.m the depth of snow will be 1.5×4=6 inches.

If we want to calculate the total depth of snow from midnight to 7:00 am we need to add 6 inches in 3(x-4) where 4≤x<7

Therefore,

S(x)=3(x-4)+6\ \ \ 4\leq x

7:00 a.m. to 9:00 a.m., snow was  falling at a constant rate of 2 inches per hour.

From mid night to 7:00 a.m the depth of snow will be 3(7-4)+6=15 inches.

If we want to calculate the total depth of snow from midnight to 9:00 am we need to add 15 inches in 2(x-7) where 7≤x≤9

S(x)=2(x-7)+15\ \ \ 7\leq x\leq 9

Therefore, the required piece-wise linear function is

\left\{\begin{matrix}1.5x & 0\leq x

8 0
3 years ago
NEED HELP I need to fill in the highlighted parts
Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

Prove \ x = \dfrac{62}{9}

Statement                   {} Reason

S1. 9·(x + 6) - 41 = 75   {}  R1. <u>Given</u>

S2. 9·(x + 6)  =  116        {}R2. <u>Addition property</u>

S3. <u>9·x + 54 = 116 </u>         {}R3. Distributive property

S4. 9·x = 62                   {}R4. <u>Subtraction property</u>

S5. x = \dfrac{62}{9}                     {} R5. <u>Division property of equality</u>

Question 2.

Statement                                     {}        Reason

S1. m∠A + m∠B = m∠D   {}                     R1.  Given

S2. ∠C and ∠D form a Linear Pair   {}   R2. Definition of linear pair

S3. ∠C and ∠D are supplementary   {}R3. <u>Linear pair ∠s are supplementary</u>

S4. <u>∠C + ∠D = 180° </u>  {}                           R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180°   {}         R5. <u>Substitution property</u>

Question 3.

Statement                                     {} Reason

S1. ∠BDA ≅ ∠A                             {} R1. Given

S2. ∠BDA ≅ ∠CDE                      {}  R2. <u>Vertical angle theorem</u>

S3. ∠CDE ≅ ∠A                      {}       R3. Transitive property of congruency

S4. m∠CDE = m∠A                    {}   R4. <u>Definition of congruency</u>

S5. <u>(13·x + 20)° = (14·x + 15)°</u>      {}   R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5°                       {}R6. <u>Subtraction property</u>

S7. x = 5                      {}                  R7. Subtraction property

Learn more here:

brainly.com/question/11331230

6 0
3 years ago
What is the slope of this line?
White raven [17]

Answer:

<em>m</em> = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points given from the graph.</em>

Point (0, 2)

Point (7, 2)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{2-2}{7-0}
  2. Subtract:                       m=\frac{0}{7}
  3. Divide:                          m=0

Any horizontal line will have a slope of 0.

And we have our final answer!

3 0
3 years ago
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