Use the Order of operations but don't use pemdas...use GEMS :)
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
Step-by-step explanation:
6x + 3y = -18
Taking 3 common from left side
so, 3(2x+y) = -18
2x+y = -18/3
2x+y = -6 (equation 1)
and, 7x + 7y = 0
Taking 7 as commom from left side
7(x + y) = 0
x + y = 0/7
x + y = 0 (equation 2)
now , by using elimination method
subtracting equation2 from equation1
2x + y - (x + y)= -6 - 0
2x + y - x - y = -6
x = -6
so, x = -6
substituting value of x in equation 1
2(-6) + y = -6
-12 + y = -6
y = -6 +12
y = 6
hence, the value of x = -6
and value of y = 6
Answer:
bottom right
Step-by-step explanation:
Answer:
C -1
Step-by-step explanation:
