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tia_tia [17]
3 years ago
15

What are the 3 commen factors between 24 and 32

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

\huge\text{Hey there!}

\large\textsf{24:  1, 2, 3, 4, 6, 8, 12, 24}

\large\textsf{32: 1, 2, 4, 8, 16, 32}

\large\text{COMMON FACTORS: \textsf{1, 2, 4, \& 8}}

\boxed{\boxed{\large\text{Answer: \huge \textsf{\bf 2, 4, \& 8}}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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If the area of a wall is 81, what is the length of the wall?
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Answer:

9

Step-by-step explanation:

  1. Find the square root of 81: \sqrt{81} = 9  

I hope this helps!

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19% of 43 estimated answer
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8 0
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Read 2 more answers
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
4 years ago
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