What are the 3 commen factors between 24 and 32

Mathematics

1 answer:

Elena L [17]3 years ago

7 0

$\huge\text{Hey there!}$

$\large\textsf{24: 1, 2, 3, 4, 6, 8, 12, 24}$

$\large\textsf{32: 1, 2, 4, 8, 16, 32}$

$\large\text{COMMON FACTORS: \textsf{1, 2, 4, \& 8}}$

$\boxed{\boxed{\large\text{Answer: \huge \textsf{\bf 2, 4, \& 8}}}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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Please solve the following question!!

Komok [63]

2(21x − 7) + 4(3x + 2) = 6(2x + 9) + 3
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4 0

3 years ago

In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.

REY [17]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)

m∠IKL + m∠IKC = 180° ....(1)

But ∠IKC ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

5 0

3 years ago

Read 2 more answers

An advertiser drops 10,000 leaflets on a city which has 2000 blocks. Assume that each leaflet has an equal chance of landing on

Ira Lisetskai [31]

Answer:

0.00673

Step-by-step explanation:

As each of the 10000 leaflets has equal chance on landing into 1 of the 2000 blocks, this means each leaflet has a probability of 1/2000 to land on the 1st block, 1/2000 to land on the 2nd lock, 1/2000 to land on the 3rd block, and so on.

The probability that a particular block will receive no leaflet is chance of each leaflets to land on the other 1999 blocks, which has a chance of 1999/2000. For all 10000 leaflets to happen like this independently, then the total probability is

$\left(\frac{1999}{2000}\right)^{10000} = 0.00673$