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2 years ago

What is the vertex of the graph of f(x) = |x – 13| + 11?

Mathematics

2 answers:

dybincka [34]2 years ago

8 0

Answer:

The vertex of the graph of f(x) = |x - 13| + 11 is (13, 11).

Step-by-step explanation:

There is something called absolute value in the given function. It means two equations will result from it.

When $(x -13) > 0$ the resultant equation is

$y = f(x) = x - 13 + 11 = x - 2$ - This will be the first equation

When $(x - 13) < 0$ the resultant equation is

$y = f(x) = -(x - 13) + 11 = -x + 24$ - This will be the second equation.

The intersection of these lines will give the vertex as found by solving both equations at the same time.

$y = x - 2$

$y = -x + 24$

_________

$2y = 0 + 22$

$y = \frac{22}{2} = 11$

Replacing the value of $y$ for any one;

$x = 11 + 2 = 13$ (first one)

$x = 24 - 11 = 13$ (second one)

The vertex is (13, 11)

Alinara [238K]2 years ago

6 0

Answer:

hmmmmm

Step-by-step explanation:

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Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

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Now, you will need to do a conversion:

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I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are $1*10^6$ bytes!)

In the second fraction thought, remember one kilobyte is $1*10^3$ bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do $\frac{1kilobyte}{1*10^3bytes}$ , but I think it is more correct to do write it out how I did).