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wlad13 [49]
3 years ago
7

The system of equations can be solved using linear combination to eliminate one of the variables.2x − y = −4→10x − 5y = −203x +

5y = 59→3x + 5y = 59 13x = 39Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?2x – y = –410x – 5y = –207x = 3913x = 39
Mathematics
1 answer:
frosja888 [35]3 years ago
6 0
2x − y = −4 → 10x − 5y = −20
3x + 5y = 59 → 3x + 5y = 59
13x = 39 . . . . . result of adding the two equations on the right

13x = 39 can replace 3x + 5y = 59 in the original system and still produce the same solution.
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zmey [24]
<h2>Answer:  y = 2</h2>

Step-by-step explanation:

When a line has a slope of 0, it is a horizontal line ( y = some value )

Since the line passes through the point (0, 2), then the line is y = 2

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So
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7 0
3 years ago
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4. Which of the following represents the solution set to the inequality
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3 years ago
At a high school basketball game the lions and the eagles are playing. the lions attempted 16 free throws and made 13, attempted
vampirchik [111]

<u>Answer:</u>

a. The free throw percentage obtained by the Lions is of <em>81.25%</em>.

b. The free throw percentage for the Eagles was of 37.04%.

c. The field goal percentage for the Lions was of 56.01%.

d. The field goal percentage for the Eagles was of 34.43%.

e. The Lions scored 96 points.

f. The Eagles scored 64 points.

Solution:

a. The lions attempted 16 free throws and made 13, which means lions scored 13 out of 16,

The free throw percentage obtained by the Lions = \frac{13}{16}<em> × 100 = 81.25%</em>

The free throw percentage obtained by the Lions is <em>81.25%</em>

b. The eagles attempted 27 free throws and made 7 which means 7 out of 27, so:

The free throw percentage obtained by the eagles = \frac{7}{27} × 100 = 25.92 %

The free throw percentage obtained by the eagles is 25.92 %

c. The lions attempted 51 two-point shots and made 22, and attempted 16 three-point shots and made 10.

Total attempted = 51 + 16 = 67

Total shots made = 22 + 10 = 32

The field goal percentage (two-point and three-point shots combined) for the Lions = \frac{32}{67} × 100 = 47.76 %

The field goal percentage for the Lions was of 47.76 %.

d. The eagles attempted 41 two-point shots and made 19, and attempted 16 three-point shots and made 7.

Total attempted = 41 + 19 = 60

Total shots made = 19 + 7 = 26

The field goal percentage (two-point and three-point shots combined) for the eagles= \frac{32}{67} × 100 = 43.33 %

The field goal percentage for the eagles was of 43.33 %.

e. Total goals secured by lions 13 free throws, 22 two's and 10 three's. So

Total points = 10 × 1 + 22 × 2 + 10 × 3 = 84

The Lions scored 84 points.

f. Total goals secured by eagles 7 free throws, 19 two's and 7 three's. So

Total points = 7 × 1 + 19× 2 + 7 × 3 = 66

The eagles scored 66 points.

<h3>What is percentage?</h3>

The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value.

Know more about percentage problems brainly.com/question/15583541

#SPJ4

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