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nexus9112 [7]
3 years ago
5

The __________ cipher is a method of encrypting alphabetic text by using a series of different monoalphabetic ciphers selected b

ased on the letters of a keyword.
Computers and Technology
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer:

Vigenère

Explanation:

It is a method of encrypting alphabetic text by using a form of polyalphabetic substitution. A polyalphabetic cipher is any cipher based on substitution, ie using multiple substitution of alphabets. The encryption is done using a Vigenère table.

To encrypt a message using the Vigenère Cipher you choose a keyphrase. Then repeat this keyword over and over until it is the same length as the original text; this is referred to as a keystream.

You might be interested in
(20 points). Some matrixes have very special patterns, for example, in the following matrix, the numbers in the first row are eq
Nostrana [21]

Answer:

#include <iostream>

using namespace std;

void matrix(){

   int row = 5, col = 6;

   int myarr[row][col];

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           if (i == 0){

               myarr[i][x] = (x+1)*(x+1);

          }else if ( x == 0){

               myarr[i][x] = (i+1)*(i+1)*(i+1);

           } else if ( i == x){

                myarr[i][x] = (i+1);

           } else{

                myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];

           }

        }

   }

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           cout<< myarr[i][x] << " ";

       }

       cout<< "\n";

}

}

int main(){

   matrix();

}

Explanation:

The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.

3 0
2 years ago
The while loop has two important parts: a condition that is tested and a statement or block of statements that is repeated as lo
natima [27]

Answer:

TRUE

Explanation:

The while loop is used to run the block of statement again and again until condition is TRUE. if condition false program terminate the loop and execute the next of while statement.

syntax:

initialize;

while(condition)

{

 statement;

  increment/decrement;

)

when condition is TRUE, the block of statement execute again and again.

8 0
3 years ago
What happens it the offshore team members are not able to participate in the iteration demo due to time zone/infrastructure issu
professor190 [17]

The best option that will suite is that there will be no major issues since the offshore leads and the onsite members participated in the demo with the Product Owner/Stakeholders they can cascade the feedback to the offshore members

Explanation:

Iteration demo is the review which is done to gather the immediate feedback from the stakeholders on a regular basis from the regular cadence. This demo will be one mainly to review the progress of the team and the and to cascade and show their working process

They show their working process to the owners and they and the other stakeholders and they get their review from them and so there will be no issues if the members are not able to participate

5 0
3 years ago
Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th
Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

7 0
3 years ago
Mrs. Patel uses a computer program to balance her checkbook. Which of the following best explains how the
Alexandra [31]

Answer:

c it reduces errors

Explanation:

Instead of Mrs.Patel doing it she has an online program made for checks to do it for her.

6 0
3 years ago
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