Answer:
A. The song was saved using fewer bits per second than the original song.
Explanation:
A song can be recorded on the computer or any device ranging from bit rates 96 kbps to 320 kbps.
The lesser the bitrates the lesser the quality of the audio and when we increase the bit rates, the quality of the audio recorded gradually increases.
Bitrates of 128 kbps give us a radio like quality whereas when we use bitrates of 320 kbps we get very good or CD-like quality.
According to the scenario, the most appropriate answer is option A.
Answer:
Code to the answer is shown in the explanation section
Explanation:
import java.util.Scanner;
public class Question {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter the days of the month: ");
int daysOfMonth = scan.nextInt();
int minuteOfMonth = daysOfMonth * 60 * 24;
System.out.println(minuteOfMonth);
}
}
// 60 represents the number of minutes in one hour
// 24 represents the number of hours in a day
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
