ASAP<br><br><br> What is the value of x?

A person who is 3 m tall casts a shadow that is 6 m long. At the same time, a building

podryga [215]

Answer:

13.5 meters

Step-by-step explanation:

25 / 2 = 13.5

because if a human is 3 meters tall and cast 2 times the length of himself then if a building casts 25 meters then it should be 2 times less than its shadow.

6 0

2 years ago

Compound interest

aev [14]

9514 1404 393

Answer:

4254.31

Step-by-step explanation:

The compound interest multiplier is ...

m = (1 +r/n)^(nt) . . . . annual rate r compounded n times per year, t years

For 11% compounded quarterly for 18 years, the multiplier is ...

m = (1 +0.11/4)^(4·18) = 1.0275^72 ≈ 7.0516671

If 30,000 is the future value, then the present value is ...

PV = FV/m = 30,000/7.0516671

PV ≈ 4254.31

3 0

2 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago

I would like all the help I can’t get pleaseee

expeople1 [14]

Answer:

Step-by-step explanation:

a=4 b=12

2a+3b=

2*4+3*12=

8+36=

44

a²-b+10=

4²-12+10=

4*4-2=

16-2=

14

(ab)²-(a+b)²=

(4*12)²-(4+12)²=

48²-16²=

(48+16)(48-16)=

64*32=

2048

7 0

2 years ago

Find quadratic polynomial which best fits the function f(x)=e^x and x=0, in the sense that g(0)= f(0), and g'(0) = f'(0), and g"

Dmitriy789 [7]

Let $g(x)=ax^2+bx+c$ . Then

$\begin{cases}g(0)=c\\g'(0)=b\\g''(0)=2a\end{cases}$

Meanwhile, since $f(x)=e^x$ , you have $f(0)=f'(0)=f''(0)=e^0=1$ .

It follows that $a=\dfrac12$ , $b=1$ , and $c=1$ , so that the quadratic fit for $f(x)=e^x$ that satisfies the given points is

$g(x)=\dfrac12x^2+x+1$

Note that this is just the second-order Taylor polynomial for $e^x$ about $x=0$ .

3 0

3 years ago

ASAP What is the value of x?