Y - 1 = 4y - 2/3. Move the ys over to one side, +4y crosses over to become -4y, and -1 crosses over the right side to become +1. y -4y = -2/3 + 1 -3y = 1 - 2/3 -3y = 1/3 Divide both sides by -3.
H = - 16 t² + 32 t + 9 The maximum height is at the vertex of the parabola: t = - b / (2 a ) = - 32 : ( - 32 ) = 1 s The ball will reach maximum height in 1 second. h max = - 16 * 1² + 32 * 1 + 9 = - 16 + 32 + 9 = 25 m The maximum height is 25 m.
