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Ksenya-84 [330]
3 years ago
10

Y-1=4y-2/3 y=_____ solve

Mathematics
2 answers:
Vikki [24]3 years ago
7 0
Y - 1  =  4y - 2/3.      Move the ys over to one side,  +4y crosses over to become -4y,
                                  and -1 crosses over the right side to become +1.
y -4y  = -2/3  + 1
-3y  =    1 - 2/3
-3y =  1/3          Divide both sides by -3.

-3y/-3  = (1/3) / -3.
y  =  1/3  * -1/3
y =  - 1/9

Alexxandr [17]3 years ago
4 0


y-1=4y-2/3

<em><u>-4y        -4y        </u></em>

<em>-</em>3y-1=-2/3

<em><u>+1          +1</u></em>

-3y=1-2/3

-3y=3/3-2/3

-3y=1/3      <em>/:(-3)</em>

y=1/3*(-1/3)

y=-1/9

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Step-by-step explanation:

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vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

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2 years ago
What's the answer to g/10=-9
Jlenok [28]
Times both sides by 10
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