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3 years ago

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Put the following fractions in order from smallest to largest. 1 . first (smallest) 2 . second 3 . third (largest)

1 answer:

alexgriva [62]3 years ago

3 0

Answer:

2/3, 5/7, 16/12

From least to greatest!

Smallest = 2/3, Second = 5/7, Largest = 16/12

Hope this helped :-)

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Please Help me with the problem please!

evablogger [386]

Answer:

35%

total number of 11th graders = 32+18 = 50

calculating percentage:

18÷50×100

= 36%

4 0

2 years ago

Can I plss have an answer on this i need it ASAP plss

nordsb [41]

WHAT DOES THIS MEAN???... i needa think abt this one

4 0

2 years ago

Three times the sum of a number and 4 is the same as 18 more than the number. what is the number

____ [38]

Answer:

three times the sum of a number and 4, if n were to represent the unknown number, is:

3(n + 4)

18 more than a number is:

n + 18

If these two are the same, then they are equal to each other, then:

3(n + 4) = n + 18

*Do the distributive property on the left*

3n + 12 = n + 18

*Combine like terms*

2n = 6

*Divide both sides by 2*

n = 3

The number is 3.

7 0

2 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

Identify the angle measures of PQRS.

kap26 [50]

The opposite angles of an inscribe quadrilateral are supplementary.

angle P + angle R = 180
6x + 7 + 12x + 11 = 180
18x + 18 = 180
18x = 162
x = 9

Now we will substitute in the value of x to find angle P and R.

angle P = 6(9)+7 = 61
angle R = 12(9)+11 = 119

Now we will find the value of y.

angle Q + angle S = 180
10y + 7 + 3(3y + 7) = 180
10y + 7 + 9y + 21 = 180
19y + 28 = 180
19y = 152
y = 8

Now substitute in the value of y to find angle Q and S.

angle Q = 10(8)+7 = 87
angle S = 3(3*8+7) = 93

Hope this helps :)

7 0

3 years ago