Answer:
B; (2,-4)
Step-by-step explanation:
The general equation of a straight line is;
y = mx + b
where m is the slope and b is the y-intercept
So from the question, when we look at the given equation, its slope is -1/2
mathematically, when two lines are perpendicular, the product of their slopes is -1
thus;
m1 * m2 = -1
m2 * -1/2 = -1
-m2 = -2
m2 = 2
The general equation form is;
y-y1 = m(x-x1)
where (x1,y1) = (4,0)
y-0 = 2(x-4)
y = 2x - 8
So, now we look at the point that will work for this equation
For the line that will work, if we substitute its x-value, we get the y-value
Let us take a look at option B
y = 2(2) -8 = 4-8 = -4
we can see that (2,-4) works
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Answer:
The domain is all real numbers, the range is all positive numbers and the asymptote is x = 0 so the answer is the last option.
The answer to your problem is f(x)= -12 (x-4)
Pretty sure it's x= -2. multiply everything by 3
then combine.
10= 6^x you can work it like a log and minus 10 from each side.
0= -4^x
so what raised to the power gives you -4? x=-2
