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4 years ago

The endpoints of PQ are (4,1) and Q(4,8)

Mathematics

1 answer:

tatuchka [14]4 years ago

5 0

Answer:

Search this up on google to find out what the answer is because no one is going to know how to do it.

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Can u please have help i cant get this

adell [148]

Answer:

Step-by-step explanation:

Three or more points that lie on the same line are collinear points.

I have highlighted the points so you can see where they lay on the lines. You can see only one set of points is on 2 different lines.

Please mark Brainliest when able.

7 0

3 years ago

Which pair shows equivalent expressions?2(3x+ 2) = 23 x+1<br> 21ę x+ 2) = x+4<br> 2c 21= x+4)= 2

Ket [755]

Answer:

Option (2)

Step-by-step explanation:

Option (1).

$2(\frac{2}{5}x+2)=2\frac{2}{5}x+1$

$\frac{4x}{5}+4=\frac{12}{5}x+1$

Therefore, both the sides of the expression are not equal.

False.

Option (2).

$2(\frac{2}{5}x+2)=\frac{4}{5}x+4$

$\frac{4x}{5}+4=\frac{4}{5}x+4$

True.

Option (3).

$2(\frac{2}{5}x+4)=\frac{4}{5}x+2$

$\frac{4}{5}x+8=\frac{4}{5}x+2$

False.

Option (4).

$2(\frac{2}{5}x+4)=2\frac{2}{5}x+8$

$\frac{4x}{5}+8=\frac{12}{5}x+8$

Both the sides are not equal.

False.

7 0

3 years ago

The speed of light is 3 x 10^8 meters per second. The sun is approximately 230.000.000 meters from Mars. How many seconds does i

Travka [436]

Answer:

0.8

Step-by-step explanation:

Given that:

Speed of light = 3 * 10^8 m/s

Distance of sun to Mars = 230,000,000 meters

How many seconds does it take for sunlight to reach Mars?

Using the relation :

Speed = distance / time

Hence ;

Time = Distance / Speed

Time = 2.3 * 10^8 / 3 * 10^8

Time = 0.766

Time = 0.8 ( nearest tenth)

6 0

4 years ago

Creating and solving inequality

Tom [10]

Answer:

I decided to take a picture since it was easier for me that way. Hope you don't mind. Oh and if my number line isn't clear, the answer is the first number line

5 0

3 years ago

Solve x2 – 12x + 59 = 0 for x.

lesya692 [45]

No real solutions. x2−[email protected]−12x+59=0x2−12x+59=0Step 1: Use quadratic formula with a=1, b=-12, c=59.x=−b±√b2−4ac2ax=−(−12)±√(−12)2−4(1)(59)2(1)x=12±√−922

3 0

4 years ago