Answer:
Just keep the y axis the same and instead of -3,3 it would be -3,-3
Step-by-step explanation:
No.......................
By the confront theorem we know that the limit only exists if both lateral limits are equal
In this case they aren't so we don't have limit for x approaching 2, but we can find their laterals.
Approaching 2 by the left we have it on the 5 line so this limit is 5
Approaching 2 by the right we have it on the -3 line so this limit is -3
Think: it's approaching x = 2 BUT IT'S NOT 2, and we only have a different value for x = 2 which is 1, but when it's approach by the left we have the values in the 5 line and by the right in the -3 line.
13. 39
14. 2(x+4)
15. 24
16. 11(x+5)
17. 6(4x+3y)
18. 8(2x+10y)
19. 5(2x+3)
Hope this helped☺☺
Answer: Oc. 28
Step-by-step explanation:
5^2=25
3+5^2=3+25=28
