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Artyom0805 [142]
3 years ago
12

What is the factor for 30n-40

Mathematics
1 answer:
nikitadnepr [17]3 years ago
7 0
Factor: 
<span>30n - 40 = 10(3n - 4)

hope it helps</span>
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A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line.
IgorC [24]

Answer:

a = 2

Step-by-step explanation:

Let's find the equation of the line using the 2 points given.

Let's call -1 as x_1 and -5 as y_1

also, 4 as x_2 and 5 as y_2

The equation of line is :

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

<em>Let's plug the points and get the equation of the line:</em>

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\y+5=\frac{5+5}{4+1}(x+1)\\y+5=2(x+1)\\y+5=2x+2\\y=2x-3

Now, to find a, we substitute a in x and 1 in y of the equation of the line we just got:

y=2x-3\\1=2(a)-3\\1=2a-3\\2a=4\\a=\frac{4}{2}=2

4 0
3 years ago
Read 2 more answers
What is the simplification of (-2x+4) + 2(2x+1)
melomori [17]
(-2x+4)+2(2x+1)= -2(-x-3)
4 0
3 years ago
7p²-30p + 8 how do you factor this trinomial
tamaranim1 [39]

Step-by-step explanation:

7p²-30p+8

=(p-4)(7p-2)

8 0
3 years ago
How do I solve this to find angle G?
VashaNatasha [74]

Answer:

Step-by-step explanation:

The angle at E is 90 degrees.

All tangents of a circle always meet the radius at a 90 degree angle.

90 + 67 + G = 180o    All triangles have 180 degrees. Combine left.

157 + G = 180o           Subtract 157 from both sides.

157 - 157 + G + 180 - 157

G = 23

5 0
3 years ago
Please help stuck on question
vazorg [7]

Answer:

Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}

We can write this polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

such that the terms:

(x - x₁), (x - x₂), etc...

are called the factors.

In this case, we know that the roots OF THE FACTORS

are:

(x = - 2)

(x = - (1 + √5))

(x = + 3i)

If the root of the polynomial is  x = -2, then the factor should be:

(x + 2)

which is zero when we evaluate x in -2

Then the correct option is the first one.

5 0
2 years ago
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