Answer:
4) wall = 114 ft^2
$118.56 to paint
5) 77 cm^2
Step-by-step explanation:
4) (15 x 8)-(2 x 3)=120-6=114 ft^2
114 x $1.04 = $118.56
5) (14 x 3.5) + (8 x 3.5) = 49 + 28 = 77 cm^2
a) Given
Total area = 81 feet squared.
Let the area of the square mat = x feet.
From question, area of the rectangular mat is twice that of square mat.
So, the area of the rectangular mat
feet.
Now,
Total area = 81 feet squared
Then,

Hence the area of the one rectangular mat = 2*9 = 18 feet squared
b) Let the width of the rectangular mat = y feet.
Then length of the mat = 2 y feet.
Area of the rectangle 
and area of rectangle = 18 feet squared.
So,

Width can not be negative.
Hence, the width of the rectangular mat = 3 feet
and length of the rectangular mat = 3*2 = 6 feet
Answer:
6
Step-by-step explanation:
Cost per item is found by dividing the cost by the number of items. If the woman bought n items for $120, the cost of each item is $120/n. If the woman bought 24 more items, n+24, at the same price, then the cost per item is $120/(n+24). The problem statement tells us this last cost is $16 less than the first cost:
120/(n+24) = (120/n) -16
Multiplying by n(n+24) gives ...
120n = 120(n+24) -16(n)(n+24)
0 = 120·24 -16n^2 -16·24n . . . . . . subtract 120n and collect terms
n^2 +24n -180 = 0 . . . . . . . . . . . . . divide by -16 to make the numbers smaller
(n +30)(n -6) = 0 . . . . . . . . . . . . . . factor the quadratic
The solutions to this are the values of n that make the factors zero: n = -30, n = 6. The negative value of n has no meaning in this context, so n=6 is the solution to the equation.
The woman bought 6 items.
_____
Check
When the woman bought 6 items for $120, she paid $120/6 = $20 for each of them. If she bought 6+24 = 30 items for the same money, she would pay $120/30 = $4 for each item. That amount, $4, is $16 less than the $20 she paid for each item.
Answer:
2(1g + 5h)
(2 x g) + (2 x 5h)
4g + 10h
_______
2
I don't know the options so I just did 3 possible ways it could be equal
Sophia is more correct in her solution.