I need help with the first question

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

25% of the students like football

belka [17]3 years ago

7 0

Answer:

25%

Step-by-step explanation:

Hope this helps!

You might be interested in

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 8+6x x+4 10 4x−3 , , , x<−7 −7≤x<−5 x≥−5

motikmotik

Answer:

$h(-6) = -\frac{1}{5}$

Step-by-step explanation:

Given

$h(x) =\left[\begin{array}{cc}8 + 6x\ \ &x < -7\\\frac{x + 4}{10} &-7 \le x$

Required

Determine h(-6)

To do this, we make use of:

$h(x) = \frac{x + 4}{10}$

Because $-7 \le -6$

So, we have:

$h(x) = \frac{x + 4}{10}$

$h(-6) = \frac{-6 + 4}{10}$

$h(-6) = \frac{-2}{10}$

Simplify

$h(-6) = -\frac{1}{5}$

4 0

3 years ago

Graph each absolute value function. State the domain, range, and y-intercept.

Inessa05 [86]

Answer:

i. D:All real numbers

ii.R: $y\le-2$

iii. Y-int: $b=-2.5$

Step-by-step explanation:

The given function is

$y=-\frac{1}{2} |x-1|-2$

The domain of this function are the values of x that makes the function defined.

The absolute value function is defined for all real values.

The domain is all real numbers.

ii. The range refers to the values of y for which x is defined.

$y=-\frac{1}{2} |x-1|-2$

The vertex of this function is

$(1,-2)$

The function is reflected in the x-axis.

The vertex is therefore the maximum point on the graph of the function.

The range is therefore;

$y\le-2$

Or

$(-\infty,2]$

iii. To find the y-intercept, we substitute $x=0$ into the funtion.

$y=-\frac{1}{2} |0-1|-2$

$y=-\frac{1}{2} (1)-2$

$y=-2.5$

The y-intercept is $b=-2.5$

The graph is shown in the attachment.