Question

A business knew that 30%, percent of its customers were less than 25 years old. The business wanted to increase this percentage, so they created a marketing campaign that targeted this age group. After the campaign, the business obtained a random sample of 50 customers to test H_o:p=0.3 versus ​Ha :p > 0.3, where p is the proportion of this business's customers who are less than 25 years old after the marketing campaign. After the campaign, the business obtained a random sample of 50 customers and found that 18 of those sampled were less than 25 years old. What would be the P-value for their test?

Answer 1

Answer:

The answer is "0.9258201 or $\bold{ \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times 0.7 }{50}}}}$".

Step-by-step explanation:

$\to P= 30 \ \%\\\\ \to x= 18 \\\\ \to n=50\\\\\\\hat p= \frac{x}{n} = \frac{18}{50} = 0.36 \\\\\bold{Formula:}\\\\X= \frac{\hat p -p}{\sqrt{\frac{p \times (1-p)}{n}}}$

    $= \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times (1-0.3)}{50}}}\\\\= \frac{0.36 -0.3}{\sqrt{\frac{0.3 \times 0.7 }{50}}}\\\\= \frac{0.36 -0.3}{\sqrt{\frac{0.21}{50}}}\\\\= \frac{0.06}{\sqrt{0.0042}}\\\\= \frac{0.06}{0.064807407}\\\\= 0.9258201$