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Schach [20]
2 years ago
12

30 POINTS!!!!!!!!!!!!!!! PLEASE HELP!!!!!!!

Mathematics
2 answers:
VashaNatasha [74]2 years ago
8 0
I believe the answers are Armand should choose Bump it Up if more than 500 bumper stickers are ordered, and The initial fee charged by You Name It is greater than the initial fee charged by Bump It Up.
r-ruslan [8.4K]2 years ago
7 0

Answer:

<h3>Bump It Up charges more per bumper sticker than You Name It charges.</h3><h3>The initial fee charged by You Name It is greater than the initial fee charged by Bump It Up.</h3>

Step-by-step explanation:

The second and last statements are true about the function shown in the image.

The money charged per sticker refers to the ratio between both variables. So, the ratio for You Name It is:

m_{you} =\frac{500-200}{5-0}=60

The ratio for Bump It Up is:

m_{bump} =\frac{500-100}{5-0}=80

As you can see Bump It Up has a higher ratio, that is, it charges 20 bucks more per sticker than You Name It.

The benefit of picking Bump It Up is actually if Armand needs less than 500 stickers, because after 500 it's better to use You Name It.

On the other hand, the graph shows that the initial point of You Name It is 200, and the initial point of Bump It Up is 100. So, the initial fee charges by You Name It is higher than the initial fee charges by Bump It Up.

Therefore, the right answers are the second and the last statements.

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-3(x+5)=-9
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3 years ago
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

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