Answer:
Step-by-step explanation:
Part A:
A=lw
A=(6x + 4)*(2x + 11)
multiply it out:
A=6x*2x+6x*11+4*2x+4*11
A=12x^(2)+66x+8x+44
add like terms
A=12x^(2)+<u>66x+8x</u>+44
A=12x^(2)+(66+8)x+44
A=12x^(2)+74x+44
the expression used to find area is 12x^(2)+74x+44
Part B:
this is:
a second degree trinomial
since its leading coefficient (highest degree value of the expression) is 2
and
since it has three monomials (terms that are separated by + or - signs):
12x^(2)+<u><em>74x</em></u>+44
Part C:
(not sure about this one)
all area is positive or 0 (no area), so lets find the values of x that are true:
lets find the zeros
(6x + 4)*(2x + 11)=0
6x+4=0
6x=-4
x=-4/6
x=-2/3
2x+11=0
2x=-11
x=-11/2
6*(-11/2)+4
3*(-11)+4
-33+4
-29
2*(-2/3)+11
-4/3+33/3
29/3
6*(-2/3) + 4
2*(-2)+4
-4+4
0
x is greater than (-2/3)
Thus, any real number greater than -2/3 makes
(6x + 4)*(2x + 11) equals the expression:
12x^(2)+74x+44, where x is a real number greater than -2/3
if lets say x= 1, a counting number then:
(6*1 + 4)*(2*1 + 11)=12*1^(2)+74*1+44
(6+4)*(2+11)=12*1+74+44
10*13=12+118
130=130
130 and 1 are both counting numbers, proving the closure property of polynomials
