AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
Learn more about the area and perimeter of rectangle on:
brainly.com/question/24571594
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Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)
Answer:
C.8 is my answers of the many zeros in the product of 40
