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katen-ka-za [31]
3 years ago
12

What is the area of this polygon? Enter your answer in the box

Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0
Sir, there should be a polygon displayed, we can’t just get the answer out of the blue.
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Sara is getting ready for work. She has black pants, blue pants, grey pants, a red shirt, a green shirt, a white shirt, a blue s
Nady [450]

Answer:

3 pants

3 shirts

2 sweaters

just multiply 3x3x2= 18 combinations

7 0
2 years ago
How do you evaluate this?
vitfil [10]

_6C_3=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20

3 0
3 years ago
claire mixes 2 1/2 cups of water with 1/3 cup of orange juice concentrate. Han mixes 1 2/3 cups of water with 1/4 cup of orange
cricket20 [7]

Answer:

Han's mixture tastes stronger, because...

Han's uses 6 2/3 cups of water for every 1 cup of orange juice concentrate.

Clare uses 7 1/2 cups of water for every 1 cup of orange juice concentrate.

Step-by-step explanation:

Claire

Cups of water = 2 1/2 cups

Cups of orange juice = 1/3

Cups of water for every cup of orange juice = 2 1/2 ÷ 1/3

= 5/2 × 3/1

= 15/2

= 7 1/2

Han:

Cups of water = 1 2/3 cups

Cups of orange juice = 1/4 cups

Cups of water for every cup of orange juice = 1 2/3 ÷ 1/4

= 5/3 × 4/1

= 20/3

= 6 2/3

3 0
2 years ago
A stadium has 10500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sec
Hunter-Best [27]

Answer:

1). 875 seats

2). 25 rows in each section

3). $8400

4). Saving of $360

5). 2105 tickets remained unsold

6). x = 16

Step-by-step explanation:

This question is incomplete; here is the complete question.

A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal  sections: 2 premium sections and 10 standard sections. A seat at the premium section  costs $48 per game. A seat at the standard section costs $27 per game.

1. How many seats are there in each section?

2. If there are 35 seats in each row, how many rows are in each section?

3. If all the seats in the premium section are sold out for a game, how much will the  stadium get from those ticket sales?

4. There are 50 games in each season. A season pass costs $2,040. A season pass  holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?

5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were  left?

6. Write an equation using “x” and then solve  the equation. Each VIP boxes can seat X  people. If all the seats and VIP boxes are  filled up, there are 10,628 audience in the stadium.

1). Number of seats in the stadium = 10500

Number of sections = 2 premium + 10 standard = 12

Number of seats in each section = \frac{10500}{12}=875

2). If the number of seats in each row = 35

Then number of rows in each section = \frac{875}{35}=25

3). Number of seats in 2 premium sections = 2×875 = 1750

Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000

4). Cost of one ticket in premium section = $48 per game

If the games planned in one season = 50

Then cost of the tickets = 48×50 = $2400

Cost of the season ticket = $2040

Saving on the purchase of one season ticket = 2400 - 2040 = $360

5). For a night game number of tickets sold = 8395

Total number of seats in the stadium = 10500

Tickets remained unsold = 10500 - 8395 = 2105

6). Number of seats in each VIP box = x

Number of VIP boxes = 8

Number of seats in 8 VIP boxes = 8x

Total number of tickets sold = 10500 + 8x

Total number of audience in the stadium = 10628

Then the equation will be

8x + 10500 = 10628

8x = 10628 - 10500

x = \frac{128}{8}=16

4 0
2 years ago
A particular fruit's weights are normally distributed, with a mean of 372 grams and a standard deviation of 26 grams. If you pic
Mrac [35]

Answer: 90.93%

Step-by-step explanation:

M= 372

s= 26

n=36

P(365<u><</u>x<380)

1. Find Z ----> <u>365-372</u> \sqrt{36} = -1.6     Next Z----><u>  380 - 372 </u>\sqrt{36}<u>= </u>  1.8

                           26                                               26

2.  plug into calculator to find probablity: normalcdf(-1.6 , 1.8 ) = .90927 or 90.93% that the prob is between 365 and 380

3 0
2 years ago
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