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2 years ago

9

Aniyah has 10 1/3 feet of ribbon. She wants to cut the ribbon into 1 2/5 size pieces. How many full pieces of ribbon can she cut

? helpppp

1 answer:

tekilochka [14]2 years ago

8 0

Answer:

7

Step-by-step explanation:

Because 10 1/3 divided by 1 2/5 would be 7 and something and the question is asking how many <em>full </em>pieces, so just 7

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Prove that sin^4x + cos^4x= sinxcosx

yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

$sin^4(x) + cos^4(x)$

We can rewrite this as:

$(sin^2(x))^2 + (cos^2(x))^2$

Now we can add and subtract cos^2(x)*sin^2(x) to get:

$(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)$

We can complete squares to get:

$(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2$

and we know that:

cos^2(x) + sin^2(x) = 1

then:

$1 - 2*sin(x)^2*cos(x)^2$

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

$1 - \frac{sin^2(2*x)}{2}$

Then the simplification is:

$cos^4(x) + sin^4(x) = 1 - \frac{sin^2(2*x)}{2}$

7 0

2 years ago

Is (-3, 1) a solution to this system of inequalities?

Maksim231197 [3]

Answer:

No

Step-by-step explanation:

5(-3)= -15

5(1)= 5

-15+5=-10

-10 is greater than -19 not less than or equal too.

Hope this helps!

5 0

1 year ago

Solve for j: J/-2+7=-12

Anestetic [448]

Answer:

J=38

Step-by-step explanation:

Subtract 7 to both sides so J/-2=-19

Then multiply -2 to both sides to get -19 times -2

That equals to 38

6 0

2 years ago

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

6 0

2 years ago

2-1<br> 3+2-<br> 9<br> 1<br> * 3|<br> 44<br> (+1)(0)<br> (98 9(<br> 2)

Katena32 [7]

Answer:64

Step-by-step explanation:

8 0

2 years ago