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Tomtit [17]
3 years ago
15

What is the solution of logx 729=3?

Mathematics
2 answers:
shusha [124]3 years ago
3 0

Answer:

Solution

Step-by-step explanation:

Rewrite logx729= 3 is an exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb(x)= y is equivalent to b^y = x.

X^3 = 729

Take cube root on both side and we get

x= 3√729

now we firstly simplify the 3√729

Rewrite 729 as 9^3

x = 3√9^3

pull terms out from under the redical, assuming positive real numbers

x=9

verify each of the solution by substituting them into logx729=3 and solving.

x= 9

enot [183]3 years ago
3 0

For this case we have to define properties of logarithm that:

log_ {b} (a) = c

It is equivalent to:

b^c = a

So, given the following expression we have:

log_ {x} (729) = 3

We can rewrite it as:

x ^ 3 = 729

Applying cubic root to both sides of the equation we have:

x = \sqrt [3] {729}\\x = 9

ANswer:

x = 9

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