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Tomtit [17]
3 years ago
15

What is the solution of logx 729=3?

Mathematics
2 answers:
shusha [124]3 years ago
3 0

Answer:

Solution

Step-by-step explanation:

Rewrite logx729= 3 is an exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb(x)= y is equivalent to b^y = x.

X^3 = 729

Take cube root on both side and we get

x= 3√729

now we firstly simplify the 3√729

Rewrite 729 as 9^3

x = 3√9^3

pull terms out from under the redical, assuming positive real numbers

x=9

verify each of the solution by substituting them into logx729=3 and solving.

x= 9

enot [183]3 years ago
3 0

For this case we have to define properties of logarithm that:

log_ {b} (a) = c

It is equivalent to:

b^c = a

So, given the following expression we have:

log_ {x} (729) = 3

We can rewrite it as:

x ^ 3 = 729

Applying cubic root to both sides of the equation we have:

x = \sqrt [3] {729}\\x = 9

ANswer:

x = 9

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The transformation of a function may involve any change. The function f(x) is vertically stretched and shifted 5 units upwards to form h(x).

<h3>How does the transformation of a function happen?</h3>

The transformation of a function may involve any change.

Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

Horizontal shift (also called phase shift):

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Vertical shift

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Stretching:

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  • Horizontal stretch by a factor k: y = f(\dfrac{x}{k})

The function f(x)=x^(1/3) is transformed to form the function of  h(x)=(2x)^(1/3)+5. Therefore, the transformation made to the function is,

Vertically stretched by a factor of 2^(1/3) ⇒ 2^(1/3) × x^(1/3) = (2x)^(1/3)

Up by 5 units ⇒ (2x)^(1/3) + 5

Hence, the function f(x) is vertically stretched and shifted 5 units upwards to form h(x).

Learn more about Transforming functions:

brainly.com/question/17006186

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Answer:

\huge\red{ \mid{ \underline{ \overline{ \tt  ♡ ANSWER࿐ ♡ }} \mid}}

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