Answer:
L(t) = 1100(1.87)^(t/2.4)
Corrected question;
On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 0.87 of its size every 2.4 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 1100 locusts in the population. Write a function that models the locust population t days since the first day of spring.
Step-by-step explanation:
Given;
Initial amount P = 1100
Rate of growth r = 87% = 0.87
Time step k = 2.4 days
The case above can be represented by an exponential function;
L(t) = P(1+r)^(t/k)
Where;
L(t) = locust population at time t days after the first day of spring
P = initial locust population
r = rate of increase
t = time in days
k = time step
Substituting the given values;
L(t) = 1100(1+0.87)^(t/2.4)
L(t) = 1100(1.87)^(t/2.4)
the locust population t days since the first day of spring can be modelled using the equation;
L(t) = 1100(1.87)^(t/2.4)
Answer:
x=9
y=12
Step-by-step explanation:
you know what the value of x is in terms of the second equation
so put that value into the first equation
so
-5(2y-15) + 4y = 3
-10y + 75 + 4y = 3
-6y + 75 = 3
-6y = -72
y = 12 (now we have the actual value of y, just substitute this into any of the first two original functions)
x = 2(12) - 15
x = 24 - 15
x = 9
Answer:
SAS
Step-by-step explanation:
It's the only answer that can satisfy with the figures
Answer:
54%
Step-by-step explanation:
The different from 94 to 43:
94 - 43 = 51
The percent of change:
51/94 = 0.54 or 54%
Answer
54%
= it is equal to because the absolute value of |-5| is 5