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arlik [135]
3 years ago
10

A scientist was studying a population of elephants. the first year, he counted a population of 80. over the next eight years, th

e population's numbers were 94, 100, 103, 110, 125, 120, 125, 120. the population never exceeded 125. what is the carrying capacity for this population?120124125126
Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

The carrying capacity is defined as :

The number of people, other living organisms, or crops that a region can support without environmental degradation.

Now we are given that:

The first year, he counted a population of 80. over the next eight years, the population's numbers were 94, 100, 103, 110, 125, 120, 125, 120. the population never exceeded 125.

Since the population never exceeded 125, so we can say that the carrying capacity of elephants is 125.

Answer: The carrying capacity of elephants is 125.

harkovskaia [24]3 years ago
7 0
The answer is 125 i just took the test
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Partition segment MR into a 2:1 ratio with point L. What are the coordinates of L?
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Answer:

<em>The coordinates of L are (4,5)</em>

Step-by-step explanation:

<u>Partition</u>

Given the points M(-2,-3) R(7,9), we must find a point L(x,y) such that the distance from M to L is double the distance from L to R. This means:

\overline{ML}=2.\overline{LR}

We'll apply that relation on both axes separately:

x_M-x=2(x-x_R)

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Operating:

-2-x=2x-14

Joining like terms:

3x=12

Solving:

x= 12/3=4

Now for the y-axis:

y_M-y=2(y-y_R)

-3-y=2(y-9)

Operating

-3-y=2y-18

Joining like terms:

3y=15

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y=15/3=5

Thus the coordinates of L are (4,5)

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What is the slope of the line that passes through the points (4,1) and (6, 2)?
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otez555 [7]

At the end of the third year, the worth is 10,479.64 dollars

<h2>Explanation:</h2>

This problem can be modeled by an exponential function since we have that  the car’s value depreciated steadily from year to year, that is, we have a constant ratio. So:

c(x)=ab^x \\ \\ a:Initial \ value \\ \\ b:constant \ ratio \\ \\ x:Number \ of \ years

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a=35,000

After 7 years it is worth $2,100:

Substituting \ values: \\ \\ 2,100=35,000b^7 \\ \\ b^7=0.06 \\ \\ b=\sqrt[7]{0.06} \\ \\ b=0.669

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At the end of the third year, the worth is:

c(3)=35,000(0.669)^3 \\ \\ c(3)=\$10,479.64

At the end of the third year, the worth is 10,479.64 dollars

<h2>Learn more:</h2>

Simple interest: brainly.com/question/12354888

#LearnWithBrainly

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A box is to be constructed with a rectangular base and a height of h cm. the length, l, of the box is 10 cm, and the width, w, i
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