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3 years ago

What is the answer? ____÷ (-2) = (-3)

Mathematics

1 answer:

Margaret [11]3 years ago

6 0

Answer:

6÷ (-2) = (-3)

Step-by-step explanation:

i used a calculator

but good question

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Solve this2^x=3^(x+1) what are the exact and approximate solutions

GrogVix [38]

Take the logarithm of both sides

x = $log_{2}$ (3)x + $log_{2}$ (3)

Move expression

x- $log_{2}$ (3)x = $log_{2}$ (3)

Factor out x

x(1- $log_{2}$ (3)) = $log_{2}$ (3)

Divide

x = ( $log_{2}$ (3)) / (1- $log_{2}$ (3))

7 0

3 years ago

The top of a 15-foot ladder leans against a wall, and the bottom of the ladder slides away from the wall at a rate of 4 ft/sec.

Andrej [43]

The ladder, the ground and the wall form a right triangle; the ladder length (L) is the longest side of this triangle. L^2 = h^2 + x^2, where h represents the height of the point on the wall where the ladder touches the wall, and x represents the distance of the base of the ladder from the wall.

We need dh/dt, which will be negative because the top of the ladder is sliding down the wall.

Starting with h^2 + x^2 = L^2, we differentiate (and subst. known values such as x = 5 feet and 4 ft/sec to find dh/dt. Note that since the ladder length does not change, dL/dt = 0. This leaves us with

dh dx
2h ---- + 2x ----- = 0.
dt dt

Since x^2 + h^2 = 15^2 = 225, h^2 = 225 - (5 ft)^2 = 200, or
200 ft^2 = h^2. Then h = + sqrt(200 ft^2)

Substituting this into the differential equation, above:

2[sqrt(200)] (dh/dt) + 2 (5) (4 ft/sec) = 0. Solve this for the desired quantity, dh/dt:

[sqrt(200)] (dh/dt) + (5)(4) = 0, or

dh/dt = -20 / sqrt(200) = (-1.41 ft / sec) (answer)

This result is negative because the top of the ladder is moving downward.

4 0

4 years ago

Can someone help me?! i’m stuck between two.

QveST [7]

6 feet.
9.6/8= 1.2, so 1.2*5=6.

6 0

3 years ago

A 30cm ruler sometimes measures inches on the other side.

Alisiya [41]

1inch = 2.5cm

∆ 30cm

5cm =2inch

so 30cm=12inch

4 0

2 years ago

PLEASE HELP I WILL GIVE 50 POINTS! IF YOU GIVE FAKE ANSWER I WILL REPORT YOU!!!

defon

Answer:

It looks like your first account increases linearly,

unless you have a typo and meant:

f(x) = 10,125(1.83)^x

the second

exponential and can be written as

g(r) = 9,638(1.95)^r

clearly g(r) has a higher percentage change since 1.95 > 1.83

a more interesting question might have been: When will the amount be the same?

10,125(1.83)^x = 9,638(1.95)^x

(1.83)^x = .951901...(1.95)^x

take log of both sides and use log rules

xlog1.83 = log .951901... + log 1.95

x(log 1.83 - log 1.95) = log .951901...

x = .776..

check:

f(.776..) = 10,125(1.83)^.776.. = 1618410

g(.776..) = 9,638(1.95)^.776... = 16184.10

Step-by-step explanation:

3 0

3 years ago