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ozzi
3 years ago
15

3010 divided by .20 = ?

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

Answer:

15050

Step-by-step explanation:

Fittoniya [83]3 years ago
3 0

Answer:

15050

Step-by-step explanation:

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What fractions in this list are less than 1/2? 3/6,7/15,4/9,5/8
Vedmedyk [2.9K]
All we need to do is to find a common denominator for both 1/2 and the other numbers individually:

1/2 = 3/6 (so 3/6 is not less than 1/2 - both numbers are equal)
1/2 = 15/30 and 7/15 = 14/30 (so 7/15 is less than 1/2)
1/2 = 9/18 and 4/9 = 8/18 (so 4/9 is less than 1/2)
1/2 = 4/8 (so 5/8 is not less - it's greater than 1/2)

Answer: From the list above only <u>7/15 and 4/9</u> are less than 1/2.
7 0
4 years ago
Round 1.24236 to the nearest hundredth
matrenka [14]

Answer:

1.24

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If the length of a rectangle is x + 4 and the width of the rectangle is 2x + 9 what would the perimeter of the rectangle be? be
ss7ja [257]

Hello!

To find the perimeter of any rectangle, use the formula P = 2l + 2w.

In this formula, l is the length and w is the width. Given that the width is 2x + 9 and the length is x + 4, we can find the perimeter.

P = 2(x + 4) + 2(2x + 9)

P = 2x + 8 + 4x + 18

P = 6x + 26

Therefore, the perimeter of the rectangle is 6x + 26.

5 0
4 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial &#10;u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial &#10;v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial &#10;u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial &#10;v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
Amanda uses the equation y = kx to determine how much money (y) she earns after working any number of hours (x). Amanda earned $
kondaur [170]
Given the equation y = kx
Also given that she:
earned $350 after working 40 hours
y = how much earned
x = number of hours 
Plug it in
y = kx
350 = k(40)
divide both sides by 40 to find out how much k is
8.75 = k

k = 8.75 so your answer is A.) 8.75

Hope this helps :)
6 0
3 years ago
Read 2 more answers
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