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IgorC [24]
3 years ago
5

What equation represents a line which is perpendicular to the line y=-2/5x + 5

Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:  y = 5/2 x + 5 or  more clearly:  y = \frac{5}{2}x+ 5

Step-by-step explanation:  Slope intercept form y = mx + b

m is the slope, b is the y-intercept

To write the equation for a perpendicular line

Both lines could share the y-intercept, (0,5) so the "b" term can be the same. But it may be different. The slope of a perpendicular line is the reciprocal of the original slope with the opposite sign.

So invert 2/5 to become 5/2 and change the negative sign to positive.

The resulting equation is y = 5x/2 + 5 or  y = 2.5x + 5

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Which describes the difference between secured and unsecured credit?
kramer
A secured credit is secured by something else. An example is that a home mortgage is secured by the home.
7 0
3 years ago
Read 2 more answers
Pencils cost $0.30 each and pads of paper cost $1.25 each. You have $3.30 to spend and you need 6 pencils. How many pads of pape
natta225 [31]

Answer:

6 x 0,30 = $1,80

$3,30 - $1,80 = $1,50

$1,50 - $1,25 = $0,25 (not enough money)

you can buy 1 pad of paper

<em>hope it helps.</em>

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

3 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Alon was curious if segments \overline{JK} JK start overline, J, K, end overline and \overline{NM} NM start overline, N, M, end
BartSMP [9]

The answer is A because Alon could have rotated the figure and discovered that they are congruent

6 0
3 years ago
It costs $3 to bowl a game and $2 for shoe rental.Write an expression for cost of g games.
zubka84 [21]

if you want one game and shoe rental it would be 5$.

so g=5

so for example if you were to have 4 games, you would use this expression:

4•g or 4•5

hope i helped :)

3 0
3 years ago
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