What equation represents a line which is perpendicular to the line y=-2/5x + 5
1 answer:
Answer: y = 5/2 x + 5 or more clearly:
Step-by-step explanation: Slope intercept form y = mx + b
m is the slope, b is the y-intercept
To write the equation for a perpendicular line
Both lines could share the y-intercept, (0,5) so the "b" term can be the same. But it may be different. The slope of a perpendicular line is the reciprocal of the original slope with the opposite sign.
So invert 2/5 to become 5/2 and change the negative sign to positive.
The resulting equation is y = 5x/2 + 5 or y = 2.5x + 5
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<u>Answer:</u>
<em>The value of x in log x + log 3 = log 18 is </em><em>6</em><em>.</em>
<u>Solution:</u>
From question, given that log x + log 3 = log 18 ---- eqn 1
Let us first simplify left hand side in above equation,
We know that log m + log n = log (mn) ----- eqn 2
Adding log m and log n results in the logarithm of the product of m and n (log mn)
By using eqn 2, log x + log 3 becomes log 3x.
log x + log 3 = log 3x ---- eqn 3
By substituting eqn 3 in eqn 1, we get
log 3x = log 18
Since we have log on both sides, we can cancel log and the above equation becomes,
3x = 18
Thus the value of x in log x + log3 = log18 is 6