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trasher [3.6K]
3 years ago
15

What is the product of (2p+7)(3p+4p-3)

Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer:

14p^2+43p-21

step by-step explanation:

Alex3 years ago
3 0

Answer:

The answer is C=6p3 + 29p2 + 22p – 21

Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3

                                   =    6p³     +     8p²    -     6p    + 21p²   +  28p   -     21

                                   = 6p³ + 8p² + 21p² + 28p - 6p -21

                                   = 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21

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Given: LM ∥ KN , KL ∥ NM LP = h­1 = 5 cm, MQ = h2 = 6 cm PKLMN = 42 cm Find: Area of KLMN
andreev551 [17]

Answer:

  Area = 630/11 cm² = 57 3/11 cm²

Step-by-step explanation:

  Area = (5 cm)(KN) = (6 cm)(KL)

  Perimeter = 2(KN +KL) = 42 cm

So, ...

  KN = 1.2·KL . . . . divide the area equation by 5 cm

  1.2·KL +KL = 21 cm . . . . . divide the perimeter equation by 2

  KL = (21 cm)/2.2 . . . . . . . divide by the coefficient of KL

Substituting for KL in the area equation, we have ...

  Area = (6 cm)(21 cm)/2.2 = 630/11 cm²

6 0
3 years ago
Describe the difference between numbers with positive exponents and numbers with negative exponents
Savatey [412]
Numbers with negative numbers become smaller such as decimals. Numbers with positive exponents become bigger in quantity
4 0
3 years ago
A box contains 4 bags of flour. The total mass of all 4 bags is 6kg. What is the mass of each bag in grams?
vovangra [49]

Answer:

1500 g

Step-by-step explanation:

To find the mass of each bag, we divide 6 kg by 4.

(6 kg)/4 = 1.5 kg

Now we convert 1.5 kg to g.

1 kg = 1000 g

1.5 kg * (1000 g)/(1 kg) = 1500 g

6 0
3 years ago
Given points (-2,3 and (9,3) which expression can be used to find the distance between the two points
Karolina [17]

Answer:

d = 11

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-2, 3)

Point (9, 3)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute [DF]:                    d = \sqrt{(9+2)^2+(3-3)^2}
  2. Add/Subtract:                       d = \sqrt{(11)^2+(0)^2}
  3. Simplify:                                d = \sqrt{(11)^2}
  4. Simplify:                                d = 11
4 0
3 years ago
Read 2 more answers
Are the expressions 5 to the second power and 2 to the fifth power equivalent explain how u know
Anna71 [15]

five to the second power is 5x5 which is 25.

two to the fifth power is 2x2x2x2x2 which is 32.


8 0
3 years ago
Read 2 more answers
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