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trasher [3.6K]
2 years ago
15

What is the product of (2p+7)(3p+4p-3)

Mathematics
2 answers:
Travka [436]2 years ago
7 0

Answer:

14p^2+43p-21

step by-step explanation:

Alex2 years ago
3 0

Answer:

The answer is C=6p3 + 29p2 + 22p – 21

Step-by-step explanation:

To calculate the product, we need to multiply each member of each multiplier:

(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3

                                   =    6p³     +     8p²    -     6p    + 21p²   +  28p   -     21

                                   = 6p³ + 8p² + 21p² + 28p - 6p -21

                                   = 6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21

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Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

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Cost of one Student ticket = $4.50

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Now, we get a system of equations, that if solved we can find values of x and y

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x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

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We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

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x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

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Student Tickets sold = y = 375

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