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maw [93]
3 years ago
12

How many minutes are in m hours?

Mathematics
1 answer:
notka56 [123]3 years ago
8 0

Answer:

the 2nd one (60m minutes)

Step-by-step explanation:

60 minutes in an hour, so if m is the number of hours you would times that by the number of minutes in an hour which is sixty. 60m is 60 times m

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Solve the whole problem i give brainliest please help me.
Anna11 [10]

Answer:

The inequality is 12.5v + 70 ≥ 215

and the amount of visits they can make is 12 visits

Step-by-step explanation:

if you take away (subtract) 70 from both sides, you'll get

12.5v ≥ 145

and when you divide both sides by 12.5, you'll get 11.6, or 12

3 0
3 years ago
Lara reads 10 chapters in 4 hours. At this pace, how long will it take her to read 25 chapters? Enter your answer in the box.
Oduvanchick [21]
Lara can read 10 chapters in 4 hours.

At this rate, she can read half that many chapters in half the time.
So she reads 5 chapters in 2 hours.

So Lara reads 10 chapters in 4 hours,
+ 10 chapters in 4 more hours,
+ 5 chapters in 2 more hours.

That's 25 chapters in total, and 10 hours in total, ya? :)


8 0
3 years ago
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Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &
Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as \sin (t) \ne 0,

\displaystyle \csc t = \frac{1}{\sin t}.

Therefore, \csc(t) > 0 is equivalent to \sin (t) > 0.

Consider a unit circle centered at the origin. If the terminal side of angle t intersects the unit circle at point (x,\, y), then

  • \cos (t) = x, and
  • \sin(t) = y.

For angle t,

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In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0
3 years ago
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musickatia [10]

Answer:

d. c = 100; (x – 10)²

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Note that (x+a)²=x²+2ax+a².

In our case, 2a=-20, so 'a' must be -10.

Since c=a², and a=-10, c=(-10²)=100.

Since a=-10, the perfect square is (x – 10)²

3 0
3 years ago
When the quotient of a long division problem has a remainder, it means the
Makovka662 [10]
( divisor / dividend ) does not go into the same Evenly
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3 years ago
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