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vekshin1
3 years ago
7

​When preparing a representative sample from a list of 200 customers who complained about errors in their statements, a _____ co

uld ensure the sample is balanced geographically by selecting five customers from each of four zip codes.
Computers and Technology
1 answer:
svetoff [14.1K]3 years ago
7 0

Answer: Stratified sample

Explanation:

For preparing samples of various data of companies and enterprises we need to apply probability distribution to different samples of data. Here in the question we are to apply a representative sample from a list of 200 customers who have complained about errors in their statement. So here we can apply stratified sampling where we can divide the 200 customers into separate groups. These sub groups of the customers are known as stratas. These stratas are selected based on certain characteristics which can be identified among the customers group. Here we can form subgroups based on the type of complain that has been lodged by the customer and selecting 5 customers from four zip codes. Then it would be easy to apply probability distribution to the sub groups to derive information from them.

This process would also enable a more easier and cheaper way of sampling the customer data.

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explain how a computer screen and the eye interact to produce the variety of colors that we see from the 3 colors that are actua
Dima020 [189]

Answer:

Each pixel of light coming from your computer is made up of a combination of Red, Blue and Green light of different intensities. As this pixel of light is so small your eye only "sees" the combination of those 3 pixels as the intended colour. (as opposed to just red, green and blue light) (This is also known as additive colour mixing)

5 0
2 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
What is an algorithm?
hichkok12 [17]
D. Both A and C. In my opinion though...
8 0
3 years ago
The statement x++;
natita [175]

Answer:

The correct option for the given question is option(A) i.e Increments the value currently stored in the variable x and stores that new value back in the variable x.

Explanation:

x++ is an  increment operator Their are two types of increment operator

1.Post increment

2.Pre increment.

Post increment operator assign the value first to variable then increment the value by 1.

for example

int a=7,t;

t=a++; //post increment

Pre increment operator first  increment the value by 1 then store into variable.

int  a=7,t;

t=++a; // Pre increment.

So the correct answer is option(a)

8 0
2 years ago
Text can be inserted into a presentation by
guapka [62]

Answer:

In order to insert text into a presentation, you add a text box from the insert menu. However, this could differ based on the software you are using. Hope this helps!

6 0
3 years ago
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